---
title: "トラブルシューティング"
version: 1.11
locale: ja
source: https://docs.djangoproject.com/ja/1.11/faq/troubleshooting/
canonical: https://djangodocs.dev/ja/1.11/faq/troubleshooting/
---
# トラブルシューティング

このページでは、Django アプリの開発でよく起こるエラーや問題に関するアドバイスを説明してます。

## `django-admin` 実行時の問題

### "ommand not found: django-admin"

[django-admin](/ja/1.11/ref/django-admin/) should be on your system path if you
installed Django via `python setup.py`. If it's not on your path, you can
find it in `site-packages/django/bin`, where `site-packages` is a directory
within your Python installation. Consider symlinking to [django-admin](/ja/1.11/ref/django-admin/) from some place on your path, such as
`/usr/local/bin`.

もし `django-admin` が動作せず `django-admin.py` なら動作するという場合、このドキュメントが説明しているバージョンではない Django を使っている可能性があります。 `django-admin` は Django 1.7 で導入されました。

### macOS のパーミッション

If you're using macOS, you may see the message "permission denied" when
you try to run `django-admin`. This is because, on Unix-based systems like
macOS, a file must be marked as "executable" before it can be run as a program.
To do this, open Terminal.app and navigate (using the `cd` command) to the
directory where [django-admin](/ja/1.11/ref/django-admin/) is installed, then
run the command `sudo chmod +x django-admin`.

## その他

### `UnicodeDecodeError` が発生しました。何を間違えてしまったのでしょうか？

This class of errors happen when a bytestring containing non-ASCII sequences is
transformed into a Unicode string and the specified encoding is incorrect. The
output generally looks like this:

```
UnicodeDecodeError: 'ascii' codec can't decode byte 0x?? in position ?:
ordinal not in range(128)
```

The resolution mostly depends on the context, however here are two common
pitfalls producing this error:

- Your system locale may be a default ASCII locale, like the "C" locale on
  UNIX-like systems (can be checked by the `locale` command). If it's the
  case, please refer to your system documentation to learn how you can change
  this to a UTF-8 locale.
- You created raw bytestrings, which is easy to do on Python 2:

  ```
  my_string = 'café'
  ```

  Either use the `u''` prefix or even better, add the
  `from __future__ import unicode_literals` line at the top of your file
  so that your code will be compatible with Python 3.2 which doesn't support
  the `u''` prefix.

関連資料:

- [Unicode in Django](/ja/1.11/ref/unicode/)
- <https://wiki.python.org/moin/UnicodeDecodeError>